Optimal. Leaf size=701 \[ \frac {c x \left (c d^2-a e^2-2 c d e x^n\right )}{4 a \left (c d^2+a e^2\right )^2 n \left (a+c x^{2 n}\right )^2}+\frac {c e^2 x \left (3 c d^2-a e^2-4 c d e x^n\right )}{2 a \left (c d^2+a e^2\right )^3 n \left (a+c x^{2 n}\right )}-\frac {c x \left (\left (c d^2-a e^2\right ) (1-4 n)-2 c d e (1-3 n) x^n\right )}{8 a^2 \left (c d^2+a e^2\right )^2 n^2 \left (a+c x^{2 n}\right )}+\frac {c e^4 \left (5 c d^2-a e^2\right ) x \, _2F_1\left (1,\frac {1}{2 n};\frac {1}{2} \left (2+\frac {1}{n}\right );-\frac {c x^{2 n}}{a}\right )}{a \left (c d^2+a e^2\right )^4}+\frac {c \left (c d^2-a e^2\right ) (1-4 n) (1-2 n) x \, _2F_1\left (1,\frac {1}{2 n};\frac {1}{2} \left (2+\frac {1}{n}\right );-\frac {c x^{2 n}}{a}\right )}{8 a^3 \left (c d^2+a e^2\right )^2 n^2}-\frac {c e^2 \left (3 c d^2-a e^2\right ) (1-2 n) x \, _2F_1\left (1,\frac {1}{2 n};\frac {1}{2} \left (2+\frac {1}{n}\right );-\frac {c x^{2 n}}{a}\right )}{2 a^2 \left (c d^2+a e^2\right )^3 n}+\frac {6 c e^6 x \, _2F_1\left (1,\frac {1}{n};1+\frac {1}{n};-\frac {e x^n}{d}\right )}{\left (c d^2+a e^2\right )^4}-\frac {6 c^2 d e^5 x^{1+n} \, _2F_1\left (1,\frac {1+n}{2 n};\frac {1}{2} \left (3+\frac {1}{n}\right );-\frac {c x^{2 n}}{a}\right )}{a \left (c d^2+a e^2\right )^4 (1+n)}-\frac {c^2 d e (1-3 n) (1-n) x^{1+n} \, _2F_1\left (1,\frac {1+n}{2 n};\frac {1}{2} \left (3+\frac {1}{n}\right );-\frac {c x^{2 n}}{a}\right )}{4 a^3 \left (c d^2+a e^2\right )^2 n^2 (1+n)}+\frac {2 c^2 d e^3 (1-n) x^{1+n} \, _2F_1\left (1,\frac {1+n}{2 n};\frac {1}{2} \left (3+\frac {1}{n}\right );-\frac {c x^{2 n}}{a}\right )}{a^2 \left (c d^2+a e^2\right )^3 n (1+n)}+\frac {e^6 x \, _2F_1\left (2,\frac {1}{n};1+\frac {1}{n};-\frac {e x^n}{d}\right )}{d^2 \left (c d^2+a e^2\right )^3} \]
[Out]
________________________________________________________________________________________
Rubi [A]
time = 0.48, antiderivative size = 701, normalized size of antiderivative = 1.00, number of steps
used = 16, number of rules used = 5, integrand size = 21, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.238, Rules used = {1451, 251,
1445, 1432, 371} \begin {gather*} -\frac {c^2 d e (1-3 n) (1-n) x^{n+1} \, _2F_1\left (1,\frac {n+1}{2 n};\frac {1}{2} \left (3+\frac {1}{n}\right );-\frac {c x^{2 n}}{a}\right )}{4 a^3 n^2 (n+1) \left (a e^2+c d^2\right )^2}+\frac {c (1-4 n) (1-2 n) x \left (c d^2-a e^2\right ) \, _2F_1\left (1,\frac {1}{2 n};\frac {1}{2} \left (2+\frac {1}{n}\right );-\frac {c x^{2 n}}{a}\right )}{8 a^3 n^2 \left (a e^2+c d^2\right )^2}+\frac {2 c^2 d e^3 (1-n) x^{n+1} \, _2F_1\left (1,\frac {n+1}{2 n};\frac {1}{2} \left (3+\frac {1}{n}\right );-\frac {c x^{2 n}}{a}\right )}{a^2 n (n+1) \left (a e^2+c d^2\right )^3}-\frac {c e^2 (1-2 n) x \left (3 c d^2-a e^2\right ) \, _2F_1\left (1,\frac {1}{2 n};\frac {1}{2} \left (2+\frac {1}{n}\right );-\frac {c x^{2 n}}{a}\right )}{2 a^2 n \left (a e^2+c d^2\right )^3}-\frac {c x \left ((1-4 n) \left (c d^2-a e^2\right )-2 c d e (1-3 n) x^n\right )}{8 a^2 n^2 \left (a e^2+c d^2\right )^2 \left (a+c x^{2 n}\right )}-\frac {6 c^2 d e^5 x^{n+1} \, _2F_1\left (1,\frac {n+1}{2 n};\frac {1}{2} \left (3+\frac {1}{n}\right );-\frac {c x^{2 n}}{a}\right )}{a (n+1) \left (a e^2+c d^2\right )^4}+\frac {c e^2 x \left (-a e^2+3 c d^2-4 c d e x^n\right )}{2 a n \left (a e^2+c d^2\right )^3 \left (a+c x^{2 n}\right )}+\frac {c x \left (-a e^2+c d^2-2 c d e x^n\right )}{4 a n \left (a e^2+c d^2\right )^2 \left (a+c x^{2 n}\right )^2}+\frac {6 c e^6 x \, _2F_1\left (1,\frac {1}{n};1+\frac {1}{n};-\frac {e x^n}{d}\right )}{\left (a e^2+c d^2\right )^4}+\frac {e^6 x \, _2F_1\left (2,\frac {1}{n};1+\frac {1}{n};-\frac {e x^n}{d}\right )}{d^2 \left (a e^2+c d^2\right )^3}+\frac {c e^4 x \left (5 c d^2-a e^2\right ) \, _2F_1\left (1,\frac {1}{2 n};\frac {1}{2} \left (2+\frac {1}{n}\right );-\frac {c x^{2 n}}{a}\right )}{a \left (a e^2+c d^2\right )^4} \end {gather*}
Antiderivative was successfully verified.
[In]
[Out]
Rule 251
Rule 371
Rule 1432
Rule 1445
Rule 1451
Rubi steps
\begin {align*} \int \frac {1}{\left (d+e x^n\right )^2 \left (a+c x^{2 n}\right )^3} \, dx &=\int \left (\frac {e^6}{\left (c d^2+a e^2\right )^3 \left (d+e x^n\right )^2}+\frac {6 c d e^6}{\left (c d^2+a e^2\right )^4 \left (d+e x^n\right )}-\frac {c \left (-c d^2+a e^2+2 c d e x^n\right )}{\left (c d^2+a e^2\right )^2 \left (a+c x^{2 n}\right )^3}-\frac {c e^2 \left (-3 c d^2+a e^2+4 c d e x^n\right )}{\left (c d^2+a e^2\right )^3 \left (a+c x^{2 n}\right )^2}-\frac {c e^4 \left (-5 c d^2+a e^2+6 c d e x^n\right )}{\left (c d^2+a e^2\right )^4 \left (a+c x^{2 n}\right )}\right ) \, dx\\ &=-\frac {\left (c e^4\right ) \int \frac {-5 c d^2+a e^2+6 c d e x^n}{a+c x^{2 n}} \, dx}{\left (c d^2+a e^2\right )^4}+\frac {\left (6 c d e^6\right ) \int \frac {1}{d+e x^n} \, dx}{\left (c d^2+a e^2\right )^4}-\frac {\left (c e^2\right ) \int \frac {-3 c d^2+a e^2+4 c d e x^n}{\left (a+c x^{2 n}\right )^2} \, dx}{\left (c d^2+a e^2\right )^3}+\frac {e^6 \int \frac {1}{\left (d+e x^n\right )^2} \, dx}{\left (c d^2+a e^2\right )^3}-\frac {c \int \frac {-c d^2+a e^2+2 c d e x^n}{\left (a+c x^{2 n}\right )^3} \, dx}{\left (c d^2+a e^2\right )^2}\\ &=\frac {c x \left (c d^2-a e^2-2 c d e x^n\right )}{4 a \left (c d^2+a e^2\right )^2 n \left (a+c x^{2 n}\right )^2}+\frac {c e^2 x \left (3 c d^2-a e^2-4 c d e x^n\right )}{2 a \left (c d^2+a e^2\right )^3 n \left (a+c x^{2 n}\right )}+\frac {6 c e^6 x \, _2F_1\left (1,\frac {1}{n};1+\frac {1}{n};-\frac {e x^n}{d}\right )}{\left (c d^2+a e^2\right )^4}+\frac {e^6 x \, _2F_1\left (2,\frac {1}{n};1+\frac {1}{n};-\frac {e x^n}{d}\right )}{d^2 \left (c d^2+a e^2\right )^3}-\frac {\left (6 c^2 d e^5\right ) \int \frac {x^n}{a+c x^{2 n}} \, dx}{\left (c d^2+a e^2\right )^4}+\frac {\left (c e^4 \left (5 c d^2-a e^2\right )\right ) \int \frac {1}{a+c x^{2 n}} \, dx}{\left (c d^2+a e^2\right )^4}+\frac {\left (c e^2\right ) \int \frac {\left (-3 c d^2+a e^2\right ) (1-2 n)+4 c d e (1-n) x^n}{a+c x^{2 n}} \, dx}{2 a \left (c d^2+a e^2\right )^3 n}+\frac {c \int \frac {\left (-c d^2+a e^2\right ) (1-4 n)+2 c d e (1-3 n) x^n}{\left (a+c x^{2 n}\right )^2} \, dx}{4 a \left (c d^2+a e^2\right )^2 n}\\ &=\frac {c x \left (c d^2-a e^2-2 c d e x^n\right )}{4 a \left (c d^2+a e^2\right )^2 n \left (a+c x^{2 n}\right )^2}+\frac {c e^2 x \left (3 c d^2-a e^2-4 c d e x^n\right )}{2 a \left (c d^2+a e^2\right )^3 n \left (a+c x^{2 n}\right )}-\frac {c x \left (\left (c d^2-a e^2\right ) (1-4 n)-2 c d e (1-3 n) x^n\right )}{8 a^2 \left (c d^2+a e^2\right )^2 n^2 \left (a+c x^{2 n}\right )}+\frac {c e^4 \left (5 c d^2-a e^2\right ) x \, _2F_1\left (1,\frac {1}{2 n};\frac {1}{2} \left (2+\frac {1}{n}\right );-\frac {c x^{2 n}}{a}\right )}{a \left (c d^2+a e^2\right )^4}+\frac {6 c e^6 x \, _2F_1\left (1,\frac {1}{n};1+\frac {1}{n};-\frac {e x^n}{d}\right )}{\left (c d^2+a e^2\right )^4}-\frac {6 c^2 d e^5 x^{1+n} \, _2F_1\left (1,\frac {1+n}{2 n};\frac {1}{2} \left (3+\frac {1}{n}\right );-\frac {c x^{2 n}}{a}\right )}{a \left (c d^2+a e^2\right )^4 (1+n)}+\frac {e^6 x \, _2F_1\left (2,\frac {1}{n};1+\frac {1}{n};-\frac {e x^n}{d}\right )}{d^2 \left (c d^2+a e^2\right )^3}-\frac {c \int \frac {\left (-c d^2+a e^2\right ) (1-4 n) (1-2 n)+2 c d e (1-3 n) (1-n) x^n}{a+c x^{2 n}} \, dx}{8 a^2 \left (c d^2+a e^2\right )^2 n^2}-\frac {\left (c e^2 \left (3 c d^2-a e^2\right ) (1-2 n)\right ) \int \frac {1}{a+c x^{2 n}} \, dx}{2 a \left (c d^2+a e^2\right )^3 n}+\frac {\left (2 c^2 d e^3 (1-n)\right ) \int \frac {x^n}{a+c x^{2 n}} \, dx}{a \left (c d^2+a e^2\right )^3 n}\\ &=\frac {c x \left (c d^2-a e^2-2 c d e x^n\right )}{4 a \left (c d^2+a e^2\right )^2 n \left (a+c x^{2 n}\right )^2}+\frac {c e^2 x \left (3 c d^2-a e^2-4 c d e x^n\right )}{2 a \left (c d^2+a e^2\right )^3 n \left (a+c x^{2 n}\right )}-\frac {c x \left (\left (c d^2-a e^2\right ) (1-4 n)-2 c d e (1-3 n) x^n\right )}{8 a^2 \left (c d^2+a e^2\right )^2 n^2 \left (a+c x^{2 n}\right )}+\frac {c e^4 \left (5 c d^2-a e^2\right ) x \, _2F_1\left (1,\frac {1}{2 n};\frac {1}{2} \left (2+\frac {1}{n}\right );-\frac {c x^{2 n}}{a}\right )}{a \left (c d^2+a e^2\right )^4}-\frac {c e^2 \left (3 c d^2-a e^2\right ) (1-2 n) x \, _2F_1\left (1,\frac {1}{2 n};\frac {1}{2} \left (2+\frac {1}{n}\right );-\frac {c x^{2 n}}{a}\right )}{2 a^2 \left (c d^2+a e^2\right )^3 n}+\frac {6 c e^6 x \, _2F_1\left (1,\frac {1}{n};1+\frac {1}{n};-\frac {e x^n}{d}\right )}{\left (c d^2+a e^2\right )^4}-\frac {6 c^2 d e^5 x^{1+n} \, _2F_1\left (1,\frac {1+n}{2 n};\frac {1}{2} \left (3+\frac {1}{n}\right );-\frac {c x^{2 n}}{a}\right )}{a \left (c d^2+a e^2\right )^4 (1+n)}+\frac {2 c^2 d e^3 (1-n) x^{1+n} \, _2F_1\left (1,\frac {1+n}{2 n};\frac {1}{2} \left (3+\frac {1}{n}\right );-\frac {c x^{2 n}}{a}\right )}{a^2 \left (c d^2+a e^2\right )^3 n (1+n)}+\frac {e^6 x \, _2F_1\left (2,\frac {1}{n};1+\frac {1}{n};-\frac {e x^n}{d}\right )}{d^2 \left (c d^2+a e^2\right )^3}+\frac {\left (c \left (c d^2-a e^2\right ) (1-4 n) (1-2 n)\right ) \int \frac {1}{a+c x^{2 n}} \, dx}{8 a^2 \left (c d^2+a e^2\right )^2 n^2}-\frac {\left (c^2 d e (1-3 n) (1-n)\right ) \int \frac {x^n}{a+c x^{2 n}} \, dx}{4 a^2 \left (c d^2+a e^2\right )^2 n^2}\\ &=\frac {c x \left (c d^2-a e^2-2 c d e x^n\right )}{4 a \left (c d^2+a e^2\right )^2 n \left (a+c x^{2 n}\right )^2}+\frac {c e^2 x \left (3 c d^2-a e^2-4 c d e x^n\right )}{2 a \left (c d^2+a e^2\right )^3 n \left (a+c x^{2 n}\right )}-\frac {c x \left (\left (c d^2-a e^2\right ) (1-4 n)-2 c d e (1-3 n) x^n\right )}{8 a^2 \left (c d^2+a e^2\right )^2 n^2 \left (a+c x^{2 n}\right )}+\frac {c e^4 \left (5 c d^2-a e^2\right ) x \, _2F_1\left (1,\frac {1}{2 n};\frac {1}{2} \left (2+\frac {1}{n}\right );-\frac {c x^{2 n}}{a}\right )}{a \left (c d^2+a e^2\right )^4}+\frac {c \left (c d^2-a e^2\right ) (1-4 n) (1-2 n) x \, _2F_1\left (1,\frac {1}{2 n};\frac {1}{2} \left (2+\frac {1}{n}\right );-\frac {c x^{2 n}}{a}\right )}{8 a^3 \left (c d^2+a e^2\right )^2 n^2}-\frac {c e^2 \left (3 c d^2-a e^2\right ) (1-2 n) x \, _2F_1\left (1,\frac {1}{2 n};\frac {1}{2} \left (2+\frac {1}{n}\right );-\frac {c x^{2 n}}{a}\right )}{2 a^2 \left (c d^2+a e^2\right )^3 n}+\frac {6 c e^6 x \, _2F_1\left (1,\frac {1}{n};1+\frac {1}{n};-\frac {e x^n}{d}\right )}{\left (c d^2+a e^2\right )^4}-\frac {6 c^2 d e^5 x^{1+n} \, _2F_1\left (1,\frac {1+n}{2 n};\frac {1}{2} \left (3+\frac {1}{n}\right );-\frac {c x^{2 n}}{a}\right )}{a \left (c d^2+a e^2\right )^4 (1+n)}-\frac {c^2 d e (1-3 n) (1-n) x^{1+n} \, _2F_1\left (1,\frac {1+n}{2 n};\frac {1}{2} \left (3+\frac {1}{n}\right );-\frac {c x^{2 n}}{a}\right )}{4 a^3 \left (c d^2+a e^2\right )^2 n^2 (1+n)}+\frac {2 c^2 d e^3 (1-n) x^{1+n} \, _2F_1\left (1,\frac {1+n}{2 n};\frac {1}{2} \left (3+\frac {1}{n}\right );-\frac {c x^{2 n}}{a}\right )}{a^2 \left (c d^2+a e^2\right )^3 n (1+n)}+\frac {e^6 x \, _2F_1\left (2,\frac {1}{n};1+\frac {1}{n};-\frac {e x^n}{d}\right )}{d^2 \left (c d^2+a e^2\right )^3}\\ \end {align*}
________________________________________________________________________________________
Mathematica [A]
time = 1.55, size = 1241, normalized size = 1.77 \begin {gather*} \frac {x \left (\frac {8 c d^2 e^6+8 a e^8}{d^2 n+d e n x^n}+\frac {2 c \left (c d^2+a e^2\right )^2 \left (-a e^2+c d \left (d-2 e x^n\right )\right )}{a n \left (a+c x^{2 n}\right )^2}+\frac {c \left (c d^2+a e^2\right ) \left (a^2 e^4 (1-8 n)+c^2 d^3 \left (d (-1+4 n)-2 e (-1+3 n) x^n\right )+2 a c d e^2 \left (6 d n-e (-1+11 n) x^n\right )\right )}{a^2 n^2 \left (a+c x^{2 n}\right )}+\frac {8 c^4 d^6 \, _2F_1\left (1,\frac {1}{2 n};1+\frac {1}{2 n};-\frac {c x^{2 n}}{a}\right )}{a^3}+\frac {32 c^3 d^4 e^2 \, _2F_1\left (1,\frac {1}{2 n};1+\frac {1}{2 n};-\frac {c x^{2 n}}{a}\right )}{a^2}+\frac {48 c^2 d^2 e^4 \, _2F_1\left (1,\frac {1}{2 n};1+\frac {1}{2 n};-\frac {c x^{2 n}}{a}\right )}{a}-24 c e^6 \, _2F_1\left (1,\frac {1}{2 n};1+\frac {1}{2 n};-\frac {c x^{2 n}}{a}\right )+\frac {c^4 d^6 \, _2F_1\left (1,\frac {1}{2 n};1+\frac {1}{2 n};-\frac {c x^{2 n}}{a}\right )}{a^3 n^2}+\frac {c^3 d^4 e^2 \, _2F_1\left (1,\frac {1}{2 n};1+\frac {1}{2 n};-\frac {c x^{2 n}}{a}\right )}{a^2 n^2}-\frac {c^2 d^2 e^4 \, _2F_1\left (1,\frac {1}{2 n};1+\frac {1}{2 n};-\frac {c x^{2 n}}{a}\right )}{a n^2}-\frac {c e^6 \, _2F_1\left (1,\frac {1}{2 n};1+\frac {1}{2 n};-\frac {c x^{2 n}}{a}\right )}{n^2}-\frac {6 c^4 d^6 \, _2F_1\left (1,\frac {1}{2 n};1+\frac {1}{2 n};-\frac {c x^{2 n}}{a}\right )}{a^3 n}-\frac {18 c^3 d^4 e^2 \, _2F_1\left (1,\frac {1}{2 n};1+\frac {1}{2 n};-\frac {c x^{2 n}}{a}\right )}{a^2 n}-\frac {2 c^2 d^2 e^4 \, _2F_1\left (1,\frac {1}{2 n};1+\frac {1}{2 n};-\frac {c x^{2 n}}{a}\right )}{a n}+\frac {10 c e^6 \, _2F_1\left (1,\frac {1}{2 n};1+\frac {1}{2 n};-\frac {c x^{2 n}}{a}\right )}{n}+\frac {8 e^6 \left (a e^2 (-1+n)+c d^2 (-1+7 n)\right ) \, _2F_1\left (1,\frac {1}{n};1+\frac {1}{n};-\frac {e x^n}{d}\right )}{d^2 n}-\frac {6 c^4 d^5 e x^n \, _2F_1\left (1,\frac {1+n}{2 n};\frac {1}{2} \left (3+\frac {1}{n}\right );-\frac {c x^{2 n}}{a}\right )}{a^3 (1+n)}-\frac {28 c^3 d^3 e^3 x^n \, _2F_1\left (1,\frac {1+n}{2 n};\frac {1}{2} \left (3+\frac {1}{n}\right );-\frac {c x^{2 n}}{a}\right )}{a^2 (1+n)}-\frac {70 c^2 d e^5 x^n \, _2F_1\left (1,\frac {1+n}{2 n};\frac {1}{2} \left (3+\frac {1}{n}\right );-\frac {c x^{2 n}}{a}\right )}{a (1+n)}-\frac {2 c^4 d^5 e x^n \, _2F_1\left (1,\frac {1+n}{2 n};\frac {1}{2} \left (3+\frac {1}{n}\right );-\frac {c x^{2 n}}{a}\right )}{a^3 n^2 (1+n)}-\frac {4 c^3 d^3 e^3 x^n \, _2F_1\left (1,\frac {1+n}{2 n};\frac {1}{2} \left (3+\frac {1}{n}\right );-\frac {c x^{2 n}}{a}\right )}{a^2 n^2 (1+n)}-\frac {2 c^2 d e^5 x^n \, _2F_1\left (1,\frac {1+n}{2 n};\frac {1}{2} \left (3+\frac {1}{n}\right );-\frac {c x^{2 n}}{a}\right )}{a n^2 (1+n)}+\frac {8 c^4 d^5 e x^n \, _2F_1\left (1,\frac {1+n}{2 n};\frac {1}{2} \left (3+\frac {1}{n}\right );-\frac {c x^{2 n}}{a}\right )}{a^3 n (1+n)}+\frac {32 c^3 d^3 e^3 x^n \, _2F_1\left (1,\frac {1+n}{2 n};\frac {1}{2} \left (3+\frac {1}{n}\right );-\frac {c x^{2 n}}{a}\right )}{a^2 n (1+n)}+\frac {24 c^2 d e^5 x^n \, _2F_1\left (1,\frac {1+n}{2 n};\frac {1}{2} \left (3+\frac {1}{n}\right );-\frac {c x^{2 n}}{a}\right )}{a n (1+n)}\right )}{8 \left (c d^2+a e^2\right )^4} \end {gather*}
Antiderivative was successfully verified.
[In]
[Out]
________________________________________________________________________________________
Maple [F]
time = 0.04, size = 0, normalized size = 0.00 \[\int \frac {1}{\left (d +e \,x^{n}\right )^{2} \left (a +c \,x^{2 n}\right )^{3}}\, dx\]
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Fricas [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Sympy [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int \frac {1}{{\left (a+c\,x^{2\,n}\right )}^3\,{\left (d+e\,x^n\right )}^2} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________